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In the xy-plane, the center of a circle is located at (−8, −
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17 Nov 2020, 07:41
17 Nov 2020, 07:41
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36% (02:20) wrong based on 49 sessions
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In the xy-plane, the center of a circle is located at (−8, −11). The point (−8, −8) lies inside the circle, and the point (−11, −7) lies outside the circle. If the circle’s radius is an integer, what is its area?
A. 4π
B. 9π
C. 16π
D. 25π
E. 36π
Kudos for the right solution and explanation
A. 4π
B. 9π
C. 16π
D. 25π
E. 36π
Kudos for the right solution and explanation
Re: In the xy-plane, the center of a circle is located at (−8, −
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17 Nov 2020, 15:06
17 Nov 2020, 15:06
Carcass wrote:
In the xy-plane, the center of a circle is located at (−8, −11). The point (−8, −8) lies inside the circle, and the point (−11, −7) lies outside the circle. If the circle’s radius is an integer, what is its area?
A. 4π
B. 9π
C. 16π
D. 25π
E. 36π
Kudos for the right solution and explanation
A. 4π
B. 9π
C. 16π
D. 25π
E. 36π
Kudos for the right solution and explanation
Does anyone mind explaining this answer? Thanks!
Re: In the xy-plane, the center of a circle is located at (−8, −
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17 Nov 2020, 23:34
17 Nov 2020, 23:34
2
the radius, r will be such that, d_inner<r<d_outer
here, d_inner=3 and d_outer=5
as the radius is said to be an integer, so the radius must be 4.
therefore, area A of the circle is A= pi*4^2= 16pi (c is the answer)
here, d_inner=3 and d_outer=5
as the radius is said to be an integer, so the radius must be 4.
therefore, area A of the circle is A= pi*4^2= 16pi (c is the answer)
