Carcass wrote:
If m is an even integer, then which of the following is the sum of the next two even integers greater than 4m + 1?
(A) 8m + 2
(B) 8m + 4
(C) 8m + 6
(D) 8m + 8
(E) 8m + 10
Since 4 is even, we know that 4m is EVEN, which means 4m + 1 is ODD.
So, the first even integer after 4m + 1 will be (4m + 1) + 1 (aka 4m + 2)
The next even integer after 4m + 2 will be (4m + 2) + 2 (aka 4m + 4)
So, the sum of the next two even integers greater than 4m + 1 = (4m + 2) + (4m + 4) = 8m + 6
Answer: C