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1/4^2 - 1/4*1/3 =
[#permalink]
21 Dec 2021, 06:07
21 Dec 2021, 06:07
Expert Reply
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Question Stats:
95% (01:05) correct
4% (00:27) wrong based on 23 sessions
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\((\frac{1}{4})^2 - \frac{1}{4}*\frac{1}{3} =\)
A. -1/12
B. -1/124
C. -1/48
D. 1/16
E. 1/12
A. -1/12
B. -1/124
C. -1/48
D. 1/16
E. 1/12
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: 1/4^2 - 1/4*1/3 =
[#permalink]
21 Dec 2021, 06:20
21 Dec 2021, 06:20
1
Carcass wrote:
\((\frac{1}{4})^2 - \frac{1}{4}*\frac{1}{3} =\)
A. -1/12
B. -1/124
C. -1/48
D. 1/16
E. 1/12
A. -1/12
B. -1/124
C. -1/48
D. 1/16
E. 1/12
\((\frac{1}{4})^2 - \frac{1}{4}*\frac{1}{3} = \frac{1}{4}(\frac{1}{4} - \frac{1}{3})\)
\( = \frac{1}{4}(\frac{3}{12} - \frac{4}{12})\)
\( = \frac{1}{4}(-\frac{1}{12})\)
\( = -\frac{1}{48}\)
Answer: C
gmatclubot
Re: 1/4^2 - 1/4*1/3 = [#permalink]
21 Dec 2021, 06:20
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