GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2508
Given Kudos: 1053
GPA: 3.39
In a certain deck of cards, each card has a positive integer written
[#permalink]
30 Apr 2022, 11:38
30 Apr 2022, 11:38
2
Expert Reply
1
Bookmarks
00:00
Question Stats:
54% (01:39) correct
45% (02:50) wrong based on 11 sessions
Hide Show timer Statistics
In a certain deck of cards, each card has a positive integer written on it. In a multiplication game, a child draws a card and multiplies the integer on the card by the next larger integer. If each possible product is between 15 and 200, then the least and greatest integers on the cards could be
A. 3 and 15
B. 3 and 20
C. 4 and 13
D. 4 and 14
E. 5 and 14
A. 3 and 15
B. 3 and 20
C. 4 and 13
D. 4 and 14
E. 5 and 14
Re: In a certain deck of cards, each card has a positive integer written
[#permalink]
03 May 2022, 23:56
03 May 2022, 23:56
Hi OP. Would love to hear the solution for the problem. Thanks
Re: In a certain deck of cards, each card has a positive integer written
[#permalink]
04 May 2022, 02:41
04 May 2022, 02:41
1
Expert Reply
2
Bookmarks
Given: 15<x(x+1)<200.
Now, it's better to test the answer choices here rather than to solve:
If x=3 then x(x+1)=12<15 --> discard A and B;
If x=4 then x(x+1)=20>15 --> so, the least value is 4, discard E. Test for the largest value: if x=14 then x(x+1)=14*15=210>200 --> discard D.
Answer: C.
Now, it's better to test the answer choices here rather than to solve:
If x=3 then x(x+1)=12<15 --> discard A and B;
If x=4 then x(x+1)=20>15 --> so, the least value is 4, discard E. Test for the largest value: if x=14 then x(x+1)=14*15=210>200 --> discard D.
Answer: C.
