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In a triangle with sides of lengths 3, 4, and 5, the smalles
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19 Mar 2019, 10:47
19 Mar 2019, 10:47
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In a triangle with sides of lengths 3, 4, and 5, the smallest angle is 36.87°. In the figure, O is the center of the circle of radius 5. A and B are two points on the circle, and the distance between the points is 6. What is the value of x ?
(A) 36.87
(B) 45
(C) 53.13
(D) 116.86
(E) 126.86
Show: ::
Attachment:
2019-04-04_1007.png [ 18.93 KiB | Viewed 3769 times ]
Re: In a triangle with sides of lengths 3, 4, and 5, the smalles
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15 Apr 2020, 06:49
15 Apr 2020, 06:49
1
Carcass wrote:
In a triangle with sides of lengths 3, 4, and 5, the smallest angle is 36.87°. In the figure, O is the center of the circle of radius 5. A and B are two points on the circle, and the distance between the points is 6. What is the value of x ?
(A) 36.87
(B) 45
(C) 53.13
(D) 116.86
(E) 126.86
(A) 36.87
(B) 45
(C) 53.13
(D) 116.86
(E) 126.86
Show: ::
Attachment:
The attachment 2019-04-04_1007.png is no longer available
Attachment:
#greprepclub In a triangle with sides of lengths.jpg [ 45.28 KiB | Viewed 2039 times ]
Plz refer to the diag. above
Fig 1 : is a 3:4:5 \( \triangle\)
and the angles are 36.87 : 53.13 : 90 (since the smallest \(\angle \)is 36.87 given)
Now, let us look into fig 2
since OA = OB = radius of the circle = 5, so the line OC divides the side AB into two equal parts. As a result two 3:4:5 \(\triangle \)s are formed
Now, in fig 3
we have a 3:4:5\( \triangle
\)
and since the smallest \(\angle\) = COB = 36.87,
therefore \(\angle x = 53.13\) degree
Re: In a triangle with sides of lengths 3, 4, and 5, the smalles
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05 Feb 2022, 04:12
05 Feb 2022, 04:12
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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