94d33m wrote:
Points P, Q, and R lie in the coordinate plane. If P = (1,5), Q=(1,1) and R = (7,y), how many different integer values for y could be chosen to form Triangle PQR, such that none of the angles in Triangle PQR is greater than 90° ?
(A) 0
(B) 3
(C) 5
(D) 7
(E) It cannot be determined from the information given
Source: Mahattan Prep 3 ( Geometry, Medium Practice Question Set, Q2)
(Refer to the figure below)
Mark the point P and Q on a graph.
Since, point R has x-coordinate as 7, draw a line of x = 7.
We have been given that the triangle cannot have any angle greater than 90° i.e. the y-coordinate of point R cannot go beyond the y value of point P (y = 5) and y value of point Q (y = 1).
The available options for y-coordinate of point R is 1, 2, 3, 4, and 5
Hence, option C
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Points P, Q, and R lie in the coordinate plane..png [ 22.37 KiB | Viewed 1042 times ]