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Re: Alice’s take-home pay last year was the same each month, and [#permalink]
2
Let her total earnings be : x
Let the fraction that she saved every month be : y

Amount not saved every month : (x-y)

According to the question :

Total savings at year end = 3* amout not saved i.e.

12*y = 3* (x-y)
Which is

y = (1/5) x

So the correct option is D

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Re: Alice’s take-home pay last year was the same each month, and [#permalink]
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Carcass wrote:
Alice’s take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she had saved at the end of the year was 3 times the amount of that portion of her monthly take-home pay that she did NOT save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month?

A. 1/2
B. 1/3
C. 1/4
D. 1/5
E. 1/6


OA is E?
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Re: Alice’s take-home pay last year was the same each month, and [#permalink]
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Fixed. It is D

I do not know why showed E

regards
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Re: Alices take-home pay last year was the same each month, and [#permalink]
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Re: Alices take-home pay last year was the same each month, and [#permalink]
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