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The product of three positive integers is 300. If one of the
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07 Sep 2014, 06:28
07 Sep 2014, 06:28
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The product of three positive integers is 300. If one of them is 5, what is the least possible value of the sum of the other two?
A. 16
B. 17
C. 19
D. 23
E. 32
A. 16
B. 17
C. 19
D. 23
E. 32
Re: GRE Math Challenge #16-three positive integers is 300
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20 Nov 2017, 07:48
20 Nov 2017, 07:48
1
a*b*5 = 300
a*b = 60
we know,
5*12 = 60
6*10 = 60
30*2 = 60
60*1 = 60
least value of a+b = 10+6 = 16
Option (A) is the answer
a*b = 60
we know,
5*12 = 60
6*10 = 60
30*2 = 60
60*1 = 60
least value of a+b = 10+6 = 16
Option (A) is the answer
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Re: The product of three positive integers is 300. If one of the
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09 Dec 2023, 01:44
09 Dec 2023, 01:44
1
The product of three positive integers is 300. If one of them is 5
Let the other two numbers be x and y
=> x * y * 5 = 300
=> xy = \(\frac{300}{5}\) = 60
What is the least possible value of the sum of the other two?
We need to find the minimum value of x + y
Sum of two numbers is minimum when either they are equal or are close to each other
\(\sqrt{60}\) between 7 and 8
So, we need to find numbers close to 7 and 8
60 can be written as 6 * 10
No other numbers apart from these two are closer to each other whose product = 60
=> Minimum sum = 6 + 10 = 16
So, Answer will be A
Hope it helps!
Let the other two numbers be x and y
=> x * y * 5 = 300
=> xy = \(\frac{300}{5}\) = 60
What is the least possible value of the sum of the other two?
We need to find the minimum value of x + y
Sum of two numbers is minimum when either they are equal or are close to each other
\(\sqrt{60}\) between 7 and 8
So, we need to find numbers close to 7 and 8
60 can be written as 6 * 10
No other numbers apart from these two are closer to each other whose product = 60
=> Minimum sum = 6 + 10 = 16
So, Answer will be A
Hope it helps!
