Carcass wrote:
Prizes will be randomly awarded to three different people in a room of 50 people. If you are one of these people, what is the probability that you will win one of the prizes?
(A) 2%
(B) 3%
(C) 4%
(D) 5%
(E) 6%
Strategy: We can solve this using counting techniques or by applying probability rules. I find that applying probability rules is typically faster. So let's go with that. P(I win a prize) = 1 -
P(I don't win a prize)P(I don't win a prize)P(I don't win a prize) = P(I don't win the 1st prize
AND I don't win the 2nd prize
AND I don't win the 3rd prize)
= P(I don't win the 1st prize)
x P(I don't win the 2nd prize)
x P(I don't win the 3rd prize)
= 49/50
x 48/49
x 47/48
= 47/50
= 94/100
=
0.94So, P(I win a prize) = 1 -
0.94 = 0.06 = 6%
Answer: E