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Which of the following equations defines a line for which no
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Updated on: 14 Dec 2018, 04:22
Updated on: 14 Dec 2018, 04:22
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Question Stats:
72% (01:04) correct
27% (01:27) wrong based on 37 sessions
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Which of the following equations defines a line for which no points on the line lie in quadrant III?
A) y = –3x + 4
B) y = 3x + 4
C) y = 1/3x + 4
D) y = –3x – 4
E) y = 3x – 4
A) y = –3x + 4
B) y = 3x + 4
C) y = 1/3x + 4
D) y = –3x – 4
E) y = 3x – 4
Re: Which of the following equations defines a line for which no
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14 Dec 2018, 04:24
14 Dec 2018, 04:24
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The question asks line that does not have either x or y with NEGATIVE sign
A.\(y = –3x + 4\).......If x is negative then y is always positive............Keep....There is no points on the line lie in quadrant III.
B.\(y = 3x + 4\)........x = -2, then y = -2 Eliminate
C.\(y= \frac{X}{3}+4\)........x = -36, then y = - 9 Eliminate
D.\(y = –3x – 4\)................................x = -1 , then y = -1 Eliminate
E. \(y = 3x – 4\).................................x = -1 , then y = -7 Eliminate
Answer: A
A.\(y = –3x + 4\).......If x is negative then y is always positive............Keep....There is no points on the line lie in quadrant III.
B.\(y = 3x + 4\)........x = -2, then y = -2 Eliminate
C.\(y= \frac{X}{3}+4\)........x = -36, then y = - 9 Eliminate
D.\(y = –3x – 4\)................................x = -1 , then y = -1 Eliminate
E. \(y = 3x – 4\).................................x = -1 , then y = -7 Eliminate
Answer: A
Re: Which of the following equations defines a line for which no
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30 May 2022, 23:44
30 May 2022, 23:44
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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