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Carol is three times Alice’s age but only twice as old as Betty. Alice
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01 Apr 2021, 02:07
01 Apr 2021, 02:07
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Question Stats:
72% (01:19) correct
27% (01:46) wrong based on 29 sessions
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Carol is three times Alice’s age but only twice as old as Betty. Alice is twelve years younger than Carol. How old is Betty?
A. 6
B. 9
C. 12
D. 18
E. 24
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 6
B. 9
C. 12
D. 18
E. 24
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: Carol is three times Alice’s age but only twice as old as Betty. Alice
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01 Apr 2021, 05:34
01 Apr 2021, 05:34
Carcass wrote:
Carol is three times Alice’s age but only twice as old as Betty. Alice is twelve years younger than Carol. How old is Betty?
A. 6
B. 9
C. 12
D. 18
E. 24
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 6
B. 9
C. 12
D. 18
E. 24
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Let B = Betty's age
Carol is twice as old as Betty.
So, 2B = Carol's age
Carol is three times Alice’s age
In other words, Alice's age is 1/3 of Carol's age
So, 2B/3 = Alice's age
Alice is twelve years younger than Carol
We can write: 2B/3 = 2B - 12
Multiply both sides by 3 to get: 2B = 6B - 36
Solve: B = 9
Answer: B
Cheers,
Brent
Re: Carol is three times Alice’s age but only twice as old as Betty. Alice
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17 Oct 2021, 09:45
17 Oct 2021, 09:45
1
Let Carols age be C
C = 3A and C = 2B
A = C - 12
B = ?
A = 3A - 12
-2A = -12
A = 6
C = 3A
C = 3(6)
C = 18
B = C/2
B = 9
C = 3A and C = 2B
A = C - 12
B = ?
A = 3A - 12
-2A = -12
A = 6
C = 3A
C = 3(6)
C = 18
B = C/2
B = 9
