Re: In an increasing sequence of 10 consecutive integers
[#permalink]
19 Jul 2022, 10:37
Solution -
Say our 10 consecutive integers are x, x+1, x+2, ..., x+9.
x+(x+1)+(x+2)+(x+3)+(x+4)=560
=> (x+5)+(x+6)+(x+7)+(x+8)+(x+9)=?
Notice that the 6th term is 5 more than the 1st term, the 7th term is 5 more than the 2nd term, ..., the 10th term is 5 more than the 5th term, thus the sum of the last 5 terms is 5*5=25 greater than the sum of the first 5 terms. Therefore the answer is 560+25=585
Answer A.
Posted from my mobile device