Sorry there was a typo in the book. I find it online and fixed

Please, refer to the stem above

Thanks for pointing out.

Regards

Given: \(\frac{a+1}{a-3} - \frac{a+2}{a-4} = 0\)

Add \(\frac{a+2}{a-4}\) to both sides of the equation to get: \(\frac{a+1}{a-3} = \frac{a+2}{a-4}\)

Cross multiply to get: \((a+1)(a-4)=(a-3)(a+2)\)

Use F.O.I.L. to expand and simplify both sides: \(a^2-3a-4=a^2-a-6\)

Subtract \(a^2\) both sides: \(-3a-4=-a-6\)

Add \(3a\) both sides: \(-4=2a-6\)

Add \(6\) both sides: \(2=2a\)

Solve: \(a = 1\)

Answer: D

Cheers,
Brent

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