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If a = (b + c)/e, then c =
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23 Aug 2022, 04:20
23 Aug 2022, 04:20
Expert Reply
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Question Stats:
78% (00:53) correct
21% (04:06) wrong based on 14 sessions
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If \(a = \frac{b+c}{e}\), then c =
(A) \((a - b)e\)
(B) \(ae − b\)
(C) \(\frac{ae}{b}\)
(D) \(\frac{b+a}{e}\)
(E) \(\frac{a}{e} − b\)
(A) \((a - b)e\)
(B) \(ae − b\)
(C) \(\frac{ae}{b}\)
(D) \(\frac{b+a}{e}\)
(E) \(\frac{a}{e} − b\)
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
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GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
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GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
Retired Moderator
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If a = (b + c)/e, then c =
[#permalink]
23 Aug 2022, 06:27
23 Aug 2022, 06:27
1
Carcass wrote:
If \(a = \frac{b+c}{e}\), then c =
(A) \((a - b)e\)
(B) \(ae − b\)
(C) \(\frac{ae}{b}\)
(D) \(\frac{b+a}{e}\)
(E) \(\frac{a}{e} − b\)
(A) \((a - b)e\)
(B) \(ae − b\)
(C) \(\frac{ae}{b}\)
(D) \(\frac{b+a}{e}\)
(E) \(\frac{a}{e} − b\)
GIVEN: \(a = \frac{b+c}{e}\)
Multiply both sides by e to get: \(ae = b + c\)
Subtract b from both sides to get: \(ae - b = c\)
Answer: B
Cheers,
Brent
gmatclubot
If a = (b + c)/e, then c = [#permalink]
23 Aug 2022, 06:27
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