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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
The rear wheels of a car crossed a certain line 0.5 second after the f
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17 Dec 2022, 10:46
17 Dec 2022, 10:46
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The rear wheels of a car crossed a certain line 0.5 second after the front wheels crossed the same line. If the centers of the front and rear wheels are 20 feet apart and the car traveled in a straight line at a constant speed, which of the following gives the speed of the car in miles per hour? (5280 feet = 1 mile)
A. \((\frac{20}{5280})(\frac{60^2}{0.5})\)
B. \((\frac{20}{5280})(\frac{60}{0.5})\)
C. \((\frac{20}{5280})(\frac{0.5}{60^2})\)
D. \(\frac{(20)(5280)}{(60^2)(0.5)}\)
E. \(\frac{(20)(5280)}{(60)(0.5)}\)
A. \((\frac{20}{5280})(\frac{60^2}{0.5})\)
B. \((\frac{20}{5280})(\frac{60}{0.5})\)
C. \((\frac{20}{5280})(\frac{0.5}{60^2})\)
D. \(\frac{(20)(5280)}{(60^2)(0.5)}\)
E. \(\frac{(20)(5280)}{(60)(0.5)}\)
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Re: The rear wheels of a car crossed a certain line 0.5 second after the f
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19 Dec 2022, 09:24
19 Dec 2022, 09:24
1
Expert Reply
We need to find the speed of the car in miles per hour. So, we should convert feet in miles and seconds in hours.
20 feet is \(\frac{20}{5280}\) miles;
0.5 second is \(\frac{0.5}{3600}=\frac{0.5}{60^2}\) hours;
The speed of the car therefore is \(\frac{distance}{time}=\frac{(\frac{20}{5280})}{(\frac{0.5}{60^2})}=(\frac{20}{5280})*(\frac{60^2}{0.5})\).
Answer: A.
20 feet is \(\frac{20}{5280}\) miles;
0.5 second is \(\frac{0.5}{3600}=\frac{0.5}{60^2}\) hours;
The speed of the car therefore is \(\frac{distance}{time}=\frac{(\frac{20}{5280})}{(\frac{0.5}{60^2})}=(\frac{20}{5280})*(\frac{60^2}{0.5})\).
Answer: A.
gmatclubot
Re: The rear wheels of a car crossed a certain line 0.5 second after the f [#permalink]
19 Dec 2022, 09:24
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