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A Cake costs 4 times the cost of a Pastry. If the cost of 11 Pastries
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17 Apr 2023, 01:32
17 Apr 2023, 01:32
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A Cake costs 4 times the cost of a Pastry. If the cost of 11 Pastries and 3 Cakes is $69 then how much would 15 Pastries cost more than 2 Cakes?
$9
$11
$15
$21
$33
$9
$11
$15
$21
$33
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2508
Given Kudos: 1053
GPA: 3.39
Re: A Cake costs 4 times the cost of a Pastry. If the cost of 11 Pastries
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19 Apr 2023, 19:42
19 Apr 2023, 19:42
1
Expert Reply
Let x be the cost of a pastry in dollars.
Then, according to the problem, the cost of a cake is 4 times the cost of a pastry, so the cost of a cake is 4x.
We know that the cost of 11 pastries and 3 cakes is $69, so we can set up an equation:
11x + 3(4x) = 69
Simplifying this equation, we get:
11x + 12x = 69
23x = 69
x = 3
So a pastry costs $3 and a cake costs 4 times that, or $12.
Now we can answer the actual question. We want to know how much 15 pastries cost more than 2 cakes.
15 pastries cost: 15x = 15(3) = $45
2 cakes cost: 2(12) = $24
So 15 pastries cost $45 - $24 = $21 more than 2 cakes.
Therefore, the answer is $21.
Then, according to the problem, the cost of a cake is 4 times the cost of a pastry, so the cost of a cake is 4x.
We know that the cost of 11 pastries and 3 cakes is $69, so we can set up an equation:
11x + 3(4x) = 69
Simplifying this equation, we get:
11x + 12x = 69
23x = 69
x = 3
So a pastry costs $3 and a cake costs 4 times that, or $12.
Now we can answer the actual question. We want to know how much 15 pastries cost more than 2 cakes.
15 pastries cost: 15x = 15(3) = $45
2 cakes cost: 2(12) = $24
So 15 pastries cost $45 - $24 = $21 more than 2 cakes.
Therefore, the answer is $21.
gmatclubot
Re: A Cake costs 4 times the cost of a Pastry. If the cost of 11 Pastries [#permalink]
19 Apr 2023, 19:42
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