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At time t = 0, a projectile was fired upward from an initial
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15 May 2019, 05:25
15 May 2019, 05:25
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85% (03:01) correct
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At time t = 0, a projectile was fired upward from an initial height of 10 feet. Its height after t seconds is given by the function \(h(t) = p−10(q −t)^2\) , where p and q are positive constants. If the projectile reached a maximum height of 100 feet when t = 3, then what was the height, in feet, of the projectile when t = 4 ?
(A) 62
(B) 70
(C) 85
(D) 89
(E) 90
(A) 62
(B) 70
(C) 85
(D) 89
(E) 90
Re: At time t = 0, a projectile was fired upward from an initial
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19 May 2019, 04:45
19 May 2019, 04:45
At t=3, h(3) = p-10(q-3)^2. We are given that height is 100 when t=3
100 = p-10(q-3)^2
100 = p – 10(q^2-6q+9)
100 = p - 10q^2+60q -90--------EQ1
At t =0, we are given that the height is 10
10 = p - 10q^2----Eq2
(EQ1)-(EQ2)
90 = 60q-90
180 = 60Q
q= 3
Lets substititute q in EQ2
10-p = -90
-p=-100
P = 100
H(4) = 100-10(3-4)^2
H(4) = 100-10 = 90
100 = p-10(q-3)^2
100 = p – 10(q^2-6q+9)
100 = p - 10q^2+60q -90--------EQ1
At t =0, we are given that the height is 10
10 = p - 10q^2----Eq2
(EQ1)-(EQ2)
90 = 60q-90
180 = 60Q
q= 3
Lets substititute q in EQ2
10-p = -90
-p=-100
P = 100
H(4) = 100-10(3-4)^2
H(4) = 100-10 = 90
Re: At time t = 0, a projectile was fired upward from an initial
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06 Dec 2024, 04:42
06 Dec 2024, 04:42
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
