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A, B, C, and D are points on a line such that point B bisect
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30 Sep 2018, 02:37
30 Sep 2018, 02:37
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A, B, C, and D are points on a line such that point B bisects line AC and point A bisects line CD. What is the ratio of AB to CD ?
(A) \(\frac{1}{4}\)
(B) \(\frac{1}{3}\)
(C) \(\frac{1}{2}\)
(D) \(\frac{2}{3}\)
(E) \(\frac{3}{4}\)
(A) \(\frac{1}{4}\)
(B) \(\frac{1}{3}\)
(C) \(\frac{1}{2}\)
(D) \(\frac{2}{3}\)
(E) \(\frac{3}{4}\)
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Re: A, B, C, and D are points on a line such that point B bisect
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07 Jun 2020, 04:00
07 Jun 2020, 04:00
1
[Refer attached image]
B bisects line AC => Let's take length of AC as 2x so AB=BC = x
A bisects line CD => AC = AD = 2x => CD = 4x
\(\frac{AB}{CD}\) = \(\frac{x}{4x}\) = \(\frac{1}{4}\)
So, answer is A
Hope it helps!
B bisects line AC => Let's take length of AC as 2x so AB=BC = x
A bisects line CD => AC = AD = 2x => CD = 4x
\(\frac{AB}{CD}\) = \(\frac{x}{4x}\) = \(\frac{1}{4}\)
So, answer is A
Hope it helps!
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Re: A, B, C, and D are points on a line such that point B bisect
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15 Jun 2020, 01:50
15 Jun 2020, 01:50
Why did you assume that AC = AD? Why not AB = AD?
BrushMyQuant wrote:
[Refer attached image]
B bisects line AC => Let's take length of AC as 2x so AB=BC = x
A bisects line CD => AC = AD = 2x => CD = 4x
\(\frac{AB}{CD}\) = \(\frac{x}{4x}\) = \(\frac{1}{4}\)
So, answer is A
Hope it helps!
B bisects line AC => Let's take length of AC as 2x so AB=BC = x
A bisects line CD => AC = AD = 2x => CD = 4x
\(\frac{AB}{CD}\) = \(\frac{x}{4x}\) = \(\frac{1}{4}\)
So, answer is A
Hope it helps!
Carcass wrote:
A, B, C, and D are points on a line such that point B bisects line AC and point A bisects line CD. What is the ratio of AB to CD ?
(A) \(\frac{1}{4}\)
(B) \(\frac{1}{3}\)
(C) \(\frac{1}{2}\)
(D) \(\frac{2}{3}\)
(E) \(\frac{3}{4}\)
(A) \(\frac{1}{4}\)
(B) \(\frac{1}{3}\)
(C) \(\frac{1}{2}\)
(D) \(\frac{2}{3}\)
(E) \(\frac{3}{4}\)
