In the above figure, what is the ratio of the total surface area of the cube to the area of the rectangle, formed by joining two vertices of the cube with the midpoints of two edges of the cube, as shown?

(A) $\(\frac{1}{6}\)$

(B) $\(\frac{12}{\sqrt{5}}\)$

(C) $\(\frac{\sqrt{6}}{12}\)$

(D) $\(\frac{1}{4}\)$

(E) $\(\frac{1}{3}\)$