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At a garage sale, prices for all the items sold were different. If t
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24 Feb 2025, 04:20
24 Feb 2025, 04:20
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Question Stats:
50% (00:40) correct
50% (04:37) wrong based on 2 sessions
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At a garage sale, prices for all the items sold were different. If the price of a radio sold at the garage sale was both the 15th highest price and the 20th lowest price amongst the prices of all the items that were sold, how many items were sold at the garage sale?
A. 33
B. 34
C. 35
D. 36
E. 37
A. 33
B. 34
C. 35
D. 36
E. 37
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Re: At a garage sale, prices for all the items sold were different. If t
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15 Mar 2025, 01:57
15 Mar 2025, 01:57
Expert Reply
We know that at a garage sale the price of a radio was both the $\(15^{\text {th \)$ highest price and the $\(20^{\text {th \)$ lowest price amongst the prices of all the items that were sold; we need to find the number of items which were sold at the garage sale.
The radio's price being the $\(15^{\text {th \)$ highest implies that there were 14 items which were priced more than it whereas its (Radio) price being the $\(20^{\text {th \)$ lowest means that there were 19 items which were priced less than it.
So, the total number of items in at the Garage sale $\(=\)$ Number of items price higher than the radio + Number of items priced less than the radio $\(+1=14+19+1=34\)$ ( 1 is added for the radio itself)
Hence the answer is (B).
The radio's price being the $\(15^{\text {th \)$ highest implies that there were 14 items which were priced more than it whereas its (Radio) price being the $\(20^{\text {th \)$ lowest means that there were 19 items which were priced less than it.
So, the total number of items in at the Garage sale $\(=\)$ Number of items price higher than the radio + Number of items priced less than the radio $\(+1=14+19+1=34\)$ ( 1 is added for the radio itself)
Hence the answer is (B).
gmatclubot
Re: At a garage sale, prices for all the items sold were different. If t [#permalink]
15 Mar 2025, 01:57
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