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If one number is selected at random from set $X$ and another number
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05 Mar 2025, 00:57
05 Mar 2025, 00:57
Expert Reply
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Question Stats:
66% (01:21) correct
33% (00:27) wrong based on 9 sessions
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\($$
\begin{gathered}
X=\{1,2,3,4,5\} \\
Y=\{11,12,13,14,15\}
\end{gathered}
$$
\)
If one number is selected at random from set $X$ and another number is selected from set $Y$, how many different sums will be obtained?
(A) 5
(B) 9
(C) 18
(D) 20
(E) 25
\begin{gathered}
X=\{1,2,3,4,5\} \\
Y=\{11,12,13,14,15\}
\end{gathered}
$$
\)
If one number is selected at random from set $X$ and another number is selected from set $Y$, how many different sums will be obtained?
(A) 5
(B) 9
(C) 18
(D) 20
(E) 25
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Re: If one number is selected at random from set $X$ and another number
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18 Mar 2025, 13:43
18 Mar 2025, 13:43
Expert Reply
We have two sets $\(X=\{1,2,3,4,5\} \& Y=\{11,12,13,14,15\}\)$; we need to find the number of different sums that can be obtained if one number is selected from set X and the other one is selected from set Y.
The minimum and the maximum sums that can be obtained by adding one element from set X and the other one from set $Y$ is $\(1+11=12 \& 5+15=20\)$ respectively.
So, all the values from $\(12 \& 20\)$, both inclusive, can be obtained by adding the values of set X and set Y.
Hence a total of $\(20-12+1=9\)$ different sums can be obtained, so the answer is (B).
The minimum and the maximum sums that can be obtained by adding one element from set X and the other one from set $Y$ is $\(1+11=12 \& 5+15=20\)$ respectively.
So, all the values from $\(12 \& 20\)$, both inclusive, can be obtained by adding the values of set X and set Y.
Hence a total of $\(20-12+1=9\)$ different sums can be obtained, so the answer is (B).
gmatclubot
Re: If one number is selected at random from set $X$ and another number [#permalink]
18 Mar 2025, 13:43
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