GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Company Z has 54 employees. If the number of employees having birthd
[#permalink]
02 Mar 2025, 23:28
02 Mar 2025, 23:28
Expert Reply
00:00
Question Stats:
0% (00:00) correct
0% (00:00) wrong based on 0 sessions
Hide Show timer Statistics
Company Z has 54 employees. If the number of employees having birthdays on Wednesday is more than the number of employees having birthdays on any other day of the week, each of which have same number of birth-days, what is the minimum number of employees having birthdays on Wednesday.
A. 6
B. 7
C. 8
D. 9
E. 12
A. 6
B. 7
C. 8
D. 9
E. 12
- Part of the project: GRE Quant & Verbal ADVANCED Daily Challenge 2025 NEW Edition - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
- Also replying to the unanswered questions
Re: Company Z has 54 employees. If the number of employees having birthd
[#permalink]
18 Mar 2025, 13:42
18 Mar 2025, 13:42
Expert Reply
We know that company $Z$ has 54 employees and the number of employees having birthday on Wednesday is more than the number of employees having birthday on any other day of the week; we need to find the minimum number of people who have their birthday on Wednesday.
Since we need to minimize the number the number of people having birthday on Wednesday, we would prefer to have people having birthdays on Wednesday close to those who have birthday on the day other than Wednesday.
As there are 7 days in a week, 7-7 persons can have birthday on different 7 days of the week, so we left with $\(54-7 \times 7=54-49=5\)$ persons out of which 3 persons can be given 3 different days other than Wednesdays and the remaining 2 can have birthdays on Wednesday only, so that Wednesday can have maximum people.
Thus the minimum possible number of people having birthday on Wednesday can be $\(7+2=9\)$
Hence the answer is (D).
Since we need to minimize the number the number of people having birthday on Wednesday, we would prefer to have people having birthdays on Wednesday close to those who have birthday on the day other than Wednesday.
As there are 7 days in a week, 7-7 persons can have birthday on different 7 days of the week, so we left with $\(54-7 \times 7=54-49=5\)$ persons out of which 3 persons can be given 3 different days other than Wednesdays and the remaining 2 can have birthdays on Wednesday only, so that Wednesday can have maximum people.
Thus the minimum possible number of people having birthday on Wednesday can be $\(7+2=9\)$
Hence the answer is (D).
gmatclubot
Re: Company Z has 54 employees. If the number of employees having birthd [#permalink]
18 Mar 2025, 13:42
Moderators:
