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What is the probability that the sum of two different single
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20 Jan 2020, 11:11
20 Jan 2020, 11:11
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What is the probability that the sum of two different single-digit prime numbers will NOT be prime?
A. \(0\)
B. \(\frac{1}{2}\)
C. \(\frac{2}{3}\)
D. \(\frac{5}{6}\)
E. \(1\)
Kudos for the right answer and explanation
A. \(0\)
B. \(\frac{1}{2}\)
C. \(\frac{2}{3}\)
D. \(\frac{5}{6}\)
E. \(1\)
Kudos for the right answer and explanation
Re: What is the probability that the sum of two different single
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20 Jan 2020, 18:27
20 Jan 2020, 18:27
2
Carcass wrote:
What is the probability that the sum of two different single-digit prime numbers will NOT be prime?
A. \(0\)
B. \(\frac{1}{2}\)
C. \(\frac{2}{3}\)
D. \(\frac{5}{6}\)
E. \(1\)
Kudos for the right answer and explanation
A. \(0\)
B. \(\frac{1}{2}\)
C. \(\frac{2}{3}\)
D. \(\frac{5}{6}\)
E. \(1\)
Kudos for the right answer and explanation
Here,
single digit prime nos. are
2 + 3
2 + 5
2 + 7
3 + 5
3 + 7
5 + 7
Out of these 6 options only 2 options, that are : \((2 + 3)\) and \((2 + 5)\) add up to prime number. Remaining 4 options will not be prime
Probability = \(\frac{4}{6} = \frac{2}{3}\)
Re: What is the probability that the sum of two different single
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26 Mar 2025, 06:47
26 Mar 2025, 06:47
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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