Since there are only 6 numbered baskets in which the balls are being kept, the pattern for the balls going in boxes numbered 1 to 6 is of 6 steps i.e. every $\(6^{\text {th \)$ ball will go into basket numbered 6 .

So, the $\(74^{\text {th (=6 \times 12+2)\)$ ball must go in the basket numbered 2 as 74 is 2 more than the multiple of 6 .

Hence the answer is (D).