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1/x^3,1/x^2,1/x,x,x^2,x^3
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28 Sep 2020, 02:45
28 Sep 2020, 02:45
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Question Stats:
40% (02:30) correct
59% (02:07) wrong based on 127 sessions
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\(\frac{1}{x^3},\frac{1}{x^2},\frac{1}{x},x,x^2,x^3\)
If \(-1<x<0\) , what is the median for the six numbers in the list above ?
A. \(\frac{1}{x}\)
B. \(x^2\)
C. \(\frac{x^2(x+1)}{2}\)
D. \(\frac{x(x^2+1)}{2}\)
E. \(\frac{x^2+1}{2x}\)
If \(-1<x<0\) , what is the median for the six numbers in the list above ?
A. \(\frac{1}{x}\)
B. \(x^2\)
C. \(\frac{x^2(x+1)}{2}\)
D. \(\frac{x(x^2+1)}{2}\)
E. \(\frac{x^2+1}{2x}\)
Re: 1/x^3,1/x^2,1/x,x,x^2,x^3
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03 Oct 2020, 10:31
03 Oct 2020, 10:31
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Given the inequality -1 <x< 0, the value of x has to be a negative fraction.
Therefore, the values 1/(x^2) and x^2 have to be the greatest values as they will result in positive values.
The values 1/x and 1/x^3 have to be the smallest values as they will result in negative integer values.
Say, the value of x = -1/3, then 1/x will be -3 and the value for 1/x^3 will be (-3)^3. Giving the value as integer values.
The two middle values of this list will therefore be x^3 and x. Dividing these two values by x to get the median will be-
x^3+x/2 which gives x(x^2+1)/2
This gives us the answer D
The most conclusive way to do it would be to take a value for x, for instance -1/3 and plug in the values to get the median.
Therefore, the values 1/(x^2) and x^2 have to be the greatest values as they will result in positive values.
The values 1/x and 1/x^3 have to be the smallest values as they will result in negative integer values.
Say, the value of x = -1/3, then 1/x will be -3 and the value for 1/x^3 will be (-3)^3. Giving the value as integer values.
The two middle values of this list will therefore be x^3 and x. Dividing these two values by x to get the median will be-
x^3+x/2 which gives x(x^2+1)/2
This gives us the answer D
The most conclusive way to do it would be to take a value for x, for instance -1/3 and plug in the values to get the median.
General Discussion
Re: 1/x^3,1/x^2,1/x,x,x^2,x^3
[#permalink]
28 Sep 2020, 02:45
28 Sep 2020, 02:45
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more theory and practice see our GRE - Math Book
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more theory and practice see our GRE - Math Book
