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GRE Math Challenge #36-number exceeds another number by 13
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19 Sep 2014, 03:13
19 Sep 2014, 03:13
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Question Stats:
100% (00:35) correct
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If one number exceeds another number by 13 & the larger number is 3/2 times the smaller number, then the smaller number is
A. 13
B. 26
C. 31
D. 39
E. 65
A. 13
B. 26
C. 31
D. 39
E. 65
Re: GRE Math Challenge #36-number exceeds another number by 13
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06 Jun 2018, 13:17
06 Jun 2018, 13:17
1
sandy wrote:
If one number exceeds another number by 13 & the larger number is 3/2 times the smaller number, then the smaller number is
A. 13
B. 26
C. 31
D. 39
E. 65
A. 13
B. 26
C. 31
D. 39
E. 65
Let the smaller number be x
so larger number = x+13
As per the question: (x)*(3/2)=x+13
3x = 2x+26
x=26
Thus the correct answer is B.
Re: GRE Math Challenge #36-number exceeds another number by 13
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06 Jun 2018, 18:05
06 Jun 2018, 18:05
a-b = 13
a=3/2b
b=?
Replacing b in place of a in equation 1, 3/2b - b = 13
b/2 = 13,
b =26
Hence the answer
a=3/2b
b=?
Replacing b in place of a in equation 1, 3/2b - b = 13
b/2 = 13,
b =26
Hence the answer
