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If 25^2 - 4(25) + 3 = (25 - 3)(25 - h), then h =

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Carcass
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If 25^2 - 4(25) + 3 = (25 - 3)(25 - h), then h = [#permalink] New post   26 Dec 2021, 11:14
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If \(25^2 - 4(25) + 3 = (25 - 3)(25 - h)\), then h =

(A) -2
(B) -1
(C) 0
(D) 1
(E) 2
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D
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Re: If 25^2 - 4(25) + 3 = (25 - 3)(25 - h), then h = [#permalink] New post   26 Dec 2021, 19:37
Carcass

Is there a typo in the stem?
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Re: If 25^2 - 4(25) + 3 = (25 - 3)(25 - h), then h = [#permalink] New post   26 Dec 2021, 23:16
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rx10 wrote:
Carcass

Is there a typo in the stem?

No Sir .........
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Re: If 25^2 - 4(25) + 3 = (25 - 3)(25 - h), then h = [#permalink] New post   27 Dec 2021, 01:33
1
There was sir. I have rectified it. It was \(25^2 - 4(25)^2 + 3\) rather than \(25^2 - 4(25) + 3\)

\(25^2 - 4(25) + 3 = 22(25-h)\)

\(625 - 100 + 3 = 22(25-h)\)

\(h = 1\)

Answer D
Carcass wrote:
rx10 wrote:
Carcass

Is there a typo in the stem?

No Sir .........
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Re: If 25^2 - 4(25) + 3 = (25 - 3)(25 - h), then h = [#permalink] New post   27 Dec 2021, 06:14
1
Carcass wrote:
If \(25^2 - 4(25) + 3 = (25 - 3)(25 - h)\), then \(h\) =

(A) -2
(B) -1
(C) 0
(D) 1
(E) 2


If we replace 25 with x, it's much easier to determine the value of h.
We get: x² - 4x + 3 = (x - 3)(x - h)
Factor the left side to get: (x - 3)(x - 1) = (x - 3)(x - h)

At this point, we can see that h = 1

Answer: D
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Re: If 25^2 - 4(25) + 3 = (25 - 3)(25 - h), then h = [#permalink]
27 Dec 2021, 06:14
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