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If x,y,z are positive and x=3 and y=5z, what's the ratio of
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Updated on: 24 Jun 2017, 03:07
Updated on: 24 Jun 2017, 03:07
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Question Stats:
75% (02:14) correct
25% (03:29) wrong based on 4 sessions
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If x,y,z are positive and x=3 and y=5z, what's the ratio of x+y: x+z?
a. \(\frac{1}{2}\)
b. \(\frac{7}{15}\)
c. \(\frac{8}{15}\)
d. \(\frac{8}{9}\)
e. \(\frac{10}{9}\)
a. \(\frac{1}{2}\)
b. \(\frac{7}{15}\)
c. \(\frac{8}{15}\)
d. \(\frac{8}{9}\)
e. \(\frac{10}{9}\)
Re: Question on ratio
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23 Jun 2017, 11:35
23 Jun 2017, 11:35
1
Cant i be solved like this?
as y=5z therefore y/z=5/1
i.e. y = 5k and z=1k
therefore x+y
+z = 3+5k/x+k
now, substitute values in k =1,2,3,... to get some values and match it with options available?
as y=5z therefore y/z=5/1
i.e. y = 5k and z=1k
therefore x+y
+z = 3+5k/x+know, substitute values in k =1,2,3,... to get some values and match it with options available?
Re: If x,y,z are positive and x=3 and y=5z, what's the ratio of
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24 Jun 2017, 03:09
24 Jun 2017, 03:09
Expert Reply
Please format the question in the proper way: using the right title, and using the expression. They are just above the corpus of the message.
Post the question in the right sub-forum.
Thank you
Post the question in the right sub-forum.
Thank you
