Given the radius of the circle is 3 (since one side of the equilateral triangle is 3)

Now the area of the circle =\(\pi * radius^2 = \pi * 3^2 = 9\pi\)

Now we need to find the area of the sector covered by the 2 equilateral triangle,

\(\frac{{Sector Area}}{{circle area}} = \frac{{Central angle}}{360}\)

Sector area =\(\frac{60}{360} * circle area =\frac{60}{360} * 9\pi = \frac{{3\pi}}{2}\)

Since there are two sectors so the total sectors not covered in shaded area =\(\frac{{6\pi}}{2}\)

Therefore the area under the shaded area = circle area - area of the 2 sectors = \(9\pi - \frac{{6\pi}}{2}= \frac{{12\pi}}{2} = 6\pi\)

Hence both are equal, i.e. option C