GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The center of the circle is O
[#permalink]
Updated on: 16 Nov 2019, 02:30
Updated on: 16 Nov 2019, 02:30
1
4
Bookmarks
00:00
Question Stats:
62% (02:24) correct
37% (02:42) wrong based on 64 sessions
Hide Show timer Statistics
Attachment:
#greprepclub The center of the circle is O.jpg [ 12.69 KiB | Viewed 16021 times ]
The center of the circle is O, and RS = ST = 4. What is the length of arc RWT?
A. \(\frac{4\pi}{3}\)
B. \(\frac{8\pi}{3}\)
C. \(\frac{16\pi}{3}\)
D. \(4\pi\)
E. \(8\pi\)
Re: The center of the circle is O
[#permalink]
03 Oct 2019, 05:37
03 Oct 2019, 05:37
3
NailItGre wrote:
Attachment:
The attachment #greprepclub The center of the circle is O.jpg is no longer available
The center of the circle is O, and RS = ST = 4. What is the length of arc RWT?
A. \(\frac{4\pi}{3}\)
B. \(\frac{8\pi}{3}\)
C. \(\frac{16\pi}{3}\)
D. \(4\pi\)
E. \(8\pi\)
Here,
RS = ST = 4
Therefore TO = RO = 4
Hence \(\triangle\) STO = \(\triangle\)SRO = Equilateral \(\triangle\)
The \(\angle\)TOR =120
ARC TWR = \(2\pi * Radius * \frac{240}{360} = 2\pi * 4 *\frac{240}{360} = \frac{16\pi}{3}\)
Attachments
Geometry.PNG [ 196.72 KiB | Viewed 15944 times ]
