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Mrs. Pearson has 4 boys and 5 girls in her class. She is to
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04 Oct 2017, 20:32
04 Oct 2017, 20:32
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Question Stats:
75% (00:55) correct
25% (01:19) wrong based on 8 sessions
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Mrs. Pearson has 4 boys and 5 girls in her class. She is to choose 2 boys and 2 girls to serve on her grading committee. If one girl and one boy leave before she can make a selection, then how many unique committees can result from the information above?
(A) 9
(B) 12
(C) 18
(D) 22
(E) 120
Kudos for correct solution.
(A) 9
(B) 12
(C) 18
(D) 22
(E) 120
Kudos for correct solution.
Re: Mrs. Pearson has 4 boys and 5 girls in her class. She is to
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04 Oct 2017, 22:05
04 Oct 2017, 22:05
1
Bunuel wrote:
Mrs. Pearson has 4 boys and 5 girls in her class. She is to choose 2 boys and 2 girls to serve on her grading committee. If one girl and one boy leave before she can make a selection, then how many unique committees can result from the information above?
(A) 9
(B) 12
(C) 18
(D) 22
(E) 120
Kudos for correct solution.
(A) 9
(B) 12
(C) 18
(D) 22
(E) 120
Kudos for correct solution.
Since one boy and one girl leaves before selection
therefore we are left with 3 boys and 4 girls out of which She has to choose two each from boy and girl
Therefore the total number of ways to select the committee = 3C2 * 4C2 = 18 ways
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Re: Mrs. Pearson has 4 boys and 5 girls in her class. She is to
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19 Dec 2017, 06:37
19 Dec 2017, 06:37
Expert Reply
Bunuel wrote:
Mrs. Pearson has 4 boys and 5 girls in her class. She is to choose 2 boys and 2 girls to serve on her grading committee. If one girl and one boy leave before she can make a selection, then how many unique committees can result from the information above?
(A) 9
(B) 12
(C) 18
(D) 22
(E) 120
(A) 9
(B) 12
(C) 18
(D) 22
(E) 120
Since one girl and one boy leave before she can make a selection, she now has 4 girls and 3 boys left. Thus, we need to determine the number of ways to select 2 girls from 4 and 2 boys from 3.
The girls can be selected in 4C2 = (4 x 3)/2! = 6 ways and the boys can be selected in 3C2 = 3 ways. Thus, the total number of ways to select the committee is 6 x 3 = 18 ways.
Answer: C
