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GRE Math Challenge #93-For every positive integer
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09 May 2015, 11:38
09 May 2015, 11:38
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Question Stats:
85% (00:22) correct
15% (00:29) wrong based on 20 sessions
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For every positive integer n greater than 1, n! Is defined as the product of the first n positive integers,
For example, 4! = (1) (2) (3) (4) = 24. What is the value of 12!/ 10!
(A) 2
(B) 66
(C) 121
(D) 132
(E) 144
For example, 4! = (1) (2) (3) (4) = 24. What is the value of 12!/ 10!
(A) 2
(B) 66
(C) 121
(D) 132
(E) 144
Re: GRE Math Challenge #93-For every positive integer
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18 Dec 2017, 07:09
18 Dec 2017, 07:09
sandy wrote:
For every positive integer n greater than 1, n! Is defined as the product of the first n positive integers,
For example, 4! = (1) (2) (3) (4) = 24. What is the value of 12!/ 10!
(A) 2
(B) 66
(C) 121
(D) 132
(E) 144
For example, 4! = (1) (2) (3) (4) = 24. What is the value of 12!/ 10!
(A) 2
(B) 66
(C) 121
(D) 132
(E) 144
Here
\(\frac{12!}{10!}\) = \(\frac{(12 * 11 * 10!)}{10!}\)= 132
Re: GRE Math Challenge #93-For every positive integer
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19 Dec 2017, 18:37
19 Dec 2017, 18:37
pranab01 wrote:
sandy wrote:
For every positive integer n greater than 1, n! Is defined as the product of the first n positive integers,
For example, 4! = (1) (2) (3) (4) = 24. What is the value of 12!/ 10!
(A) 2
(B) 66
(C) 121
(D) 132
(E) 144
For example, 4! = (1) (2) (3) (4) = 24. What is the value of 12!/ 10!
(A) 2
(B) 66
(C) 121
(D) 132
(E) 144
Here
\(\frac{12!}{10!}\) = \(\frac{(12 * 11 * 10!)}{10!}\)= 121
the answer of (12*11*10)/10! should be 132! answer is worng
