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In terms of y, what is the average (arithmetic mean) of 4y
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22 Nov 2017, 19:14
22 Nov 2017, 19:14
Expert Reply
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Question Stats:
100% (00:20) correct
0% (00:00) wrong based on 23 sessions
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In terms of y, what is the average (arithmetic mean) of 4y and 22 ?
A. 4y + 22
B. 4y + 11
C. 4y − 22
D. 2y + 11
E. 2y + 22
A. 4y + 22
B. 4y + 11
C. 4y − 22
D. 2y + 11
E. 2y + 22
Drill 1
Question: 1
Page: 521
Question: 1
Page: 521
Re: In terms of y, what is the average (arithmetic mean) of 4y
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02 Dec 2017, 10:59
02 Dec 2017, 10:59
sandy wrote:
In terms of y, what is the average (arithmetic mean) of 4y and 22 ?
A. 4y + 22
B. 4y + 11
C. 4y − 22
D. 2y + 11
E. 2y + 22
A. 4y + 22
B. 4y + 11
C. 4y − 22
D. 2y + 11
E. 2y + 22
Drill 1
Question: 1
Page: 521
Question: 1
Page: 521
Here the average of 4y and 22 = \(\frac{1}{2}\) * (4y + 22) = 2y + 11
Re: In terms of y, what is the average (arithmetic mean) of 4y
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09 Dec 2017, 19:39
09 Dec 2017, 19:39
Expert Reply
Explanation
To find the average, add up the values and divide by 2:
\(\frac{4y+22}{2}=\frac{2(2y +11)}{2}=2y +11\).
You can also Plug In on this one. If y = 3, then \(\frac{4*3+22}{2}\)=17, your target number.
Only choice (D) hits the target.
To find the average, add up the values and divide by 2:
\(\frac{4y+22}{2}=\frac{2(2y +11)}{2}=2y +11\).
You can also Plug In on this one. If y = 3, then \(\frac{4*3+22}{2}\)=17, your target number.
Only choice (D) hits the target.
