GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Vinay and Phil are driving in separate cars to Los Angeles,
[#permalink]
Updated on: 10 Jun 2021, 08:24
Updated on: 10 Jun 2021, 08:24
1
Expert Reply
3
Bookmarks
00:00
Question Stats:
35% (01:42) correct
64% (01:59) wrong based on 31 sessions
Hide Show timer Statistics
Vinay and Phil are driving in separate cars to Los Angeles, both leaving from the same place and traveling along the same route. If Vinay leaves at 1 a.m. and travels at 40 miles per hour, and Phil leaves at 5 a.m. and travels at 50 miles per hour, at what time does Phil catch up to Vinay?
A. 1 p.m.
B. 5 p.m.
C. 7 p.m.
D. 9 p.m.
E. 11 p.m.
A. 1 p.m.
B. 5 p.m.
C. 7 p.m.
D. 9 p.m.
E. 11 p.m.
Drill 3
Question: 2
Page: 528
Question: 2
Page: 528
Re: Vinay and Phil are driving in separate cars to Los Angeles,
[#permalink]
29 Dec 2017, 14:16
29 Dec 2017, 14:16
Expert Reply
Explanation
Before Phil leaves, Vinay has traveled for 4 hours; the rate formula is distance = rate × time, so Vinay has gone 40 miles per hour × 4 hours = 160 miles.
Upon leaving, Phil is gaining on Vinay at a rate of 10 miles per hour, because he travels 10 more miles per hour than Vinay.
Now your equation is 160 miles = 10 miles per hour × time, so time = 16 hours. Phil left at 5 a.m., so he’ll catch up to Vinay at 9 p.m., so the answer is choice D.
Before Phil leaves, Vinay has traveled for 4 hours; the rate formula is distance = rate × time, so Vinay has gone 40 miles per hour × 4 hours = 160 miles.
Upon leaving, Phil is gaining on Vinay at a rate of 10 miles per hour, because he travels 10 more miles per hour than Vinay.
Now your equation is 160 miles = 10 miles per hour × time, so time = 16 hours. Phil left at 5 a.m., so he’ll catch up to Vinay at 9 p.m., so the answer is choice D.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: Vinay and Phil are driving in separate cars to Los Angeles,
[#permalink]
17 Jan 2020, 10:58
17 Jan 2020, 10:58
1
1
sandy wrote:
Vinay and Phil are driving in separate cars to Los Angeles, both leaving from the same place and traveling along the same route. If Vinay leaves at 1 a.m. and travels at 40 miles per hour, and Phil leaves at 5 a.m. and travels at 50 miles per hour, at what time does Phil catch up to Vinay?
A. 1 p.m.
B. 5 p.m.
C. 7 p.m.
D. 9 p.m.
E. 11 p.m.
A. 1 p.m.
B. 5 p.m.
C. 7 p.m.
D. 9 p.m.
E. 11 p.m.
Drill 3
Question: 2
Page: 528
Question: 2
Page: 528
This is a shrinking gap question
When Phil starts driving at 5 a.m., Vinay has already been driving for 4 hours.
Vinay's speed is 40 mph
Distance = (rate)(time)
So, in those 4 hours, Vinay's travel distance = (40)(4) = 160 miles
When Phil eventually catches up to Vinay, the distance between them will have shrunk from 160 miles to 0 miles
In other words, the distance between them will have shrunk 160 miles
Phil's travel speed is 50 mph, and Vinay's travel speed is 40 mph
So, the shrink rate = 50 - 40 = 10 mph
Time = distance/rate
So, the time to shrink the gap 160 miles = 160/10 = 16 hours (from the time that Phil began driving).
Phil began driving at 5 a.m.
So the time when Phil catches up to Vinay = 5 a.m. + 16 hours = 9 p.m.
Answer: D
Cheers,
Brent
