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An article costing C dollars is sold for $100 at a loss of
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31 Dec 2017, 11:01
31 Dec 2017, 11:01
1
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Question Stats:
60% (00:44) correct
40% (01:28) wrong based on 5 sessions
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Q: An article costing C dollars is sold for $100 at a loss of x percent of the selling price. It is then resold at a profit of x percent of the new selling price S. If the difference between S and C is $1.11..., then x is
A. Undetermined
B. 80/9
C. 10
D. 95/9
E. 100/9
I have no clue what the answer to this question is. Any ideas? I got it from a post in this thread and could not find an answer. Seems much like a GRE style question as well so I thought I would post it here.
A. Undetermined
B. 80/9
C. 10
D. 95/9
E. 100/9
I have no clue what the answer to this question is. Any ideas? I got it from a post in this thread and could not find an answer. Seems much like a GRE style question as well so I thought I would post it here.
Re: An article costing C dollars is sold for $100 at a loss of
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01 Jan 2018, 03:54
01 Jan 2018, 03:54
1
As 1st condition says x= (C-100)/C .....(i)
And from second x= (S-C)/C........(ii)
We have S-C = 1.11 so from equation i & ii get
1.11 = C-100 => C= 101.11
And from second x= (S-C)/C........(ii)
We have S-C = 1.11 so from equation i & ii get
1.11 = C-100 => C= 101.11
Re: An article costing C dollars is sold for $100 at a loss of
[#permalink]
02 Jan 2018, 20:20
02 Jan 2018, 20:20
arinjay wrote:
As 1st condition says x= (C-100)/C .....(i)
And from second x= (S-C)/C........(ii)
We have S-C = 1.11 so from equation i & ii get
1.11 = C-100 => C= 101.11
And from second x= (S-C)/C........(ii)
We have S-C = 1.11 so from equation i & ii get
1.11 = C-100 => C= 101.11
well I don't know what you mean, since for the first sentence, it indicates that at a loss of x percent of selling price not directly related to C.
