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The figure shows a smaller square with sides of length y ins
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11 Dec 2017, 10:31
11 Dec 2017, 10:31
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Question Stats:
91% (01:34) correct
8% (02:27) wrong based on 23 sessions
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square (2).jpg [ 13.22 KiB | Viewed 7476 times ]
The figure shows a smaller square with sides of length y inscribed in a larger square with sides of length x. Which of the following relationships between x, y, and z must be true ?
A. \(x^2 = y^2 + z^2\)
B. \(x^2 = y^2 - z^2\)
C. \((x-z)^2 = y^2\)
D. \((x-y)^2 = z^2\)
E. \((x-z)^2 + z^2 = y^2\)
Re: The figure shows a smaller square with sides of length y ins
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12 Dec 2017, 05:56
12 Dec 2017, 05:56
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Carcass wrote:
Attachment:
The attachment square (2).jpg is no longer available
The figure shows a smaller square with sides of length y inscribed in a larger square with sides of length x. Which of the following relationships between x, y, and z must be true ?
A. \(x^2 = y^2 + z^2\)
B. \(x^2 = y^2 - z^2\)
C. \((x-z)^2 = y^2\)
D. \((x-y)^2 = z^2\)
E. \((x-z)^2 + z^2 = y^2\)
Show: :: OA
OA in 24h
Here
we can write as the attached diagram
Now since it is square and all angles are right angle triangle
therefore by Pythagoras theorem ; y is the hypotenuse and x and (x-z) are the two legs of the triangle
\((x-z)^2 + z^2 = y^2\) ; which is option E
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square %282%29.jpg [ 14.92 KiB | Viewed 7446 times ]
Re: The figure shows a smaller square with sides of length y ins
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06 Nov 2019, 03:11
06 Nov 2019, 03:11
Expert Reply
Awesome explanation 
