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Last year, a magazine charged a $50 subscription fee. This
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27 May 2018, 03:57
27 May 2018, 03:57
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Question Stats:
94% (01:16) correct
5% (01:21) wrong based on 55 sessions
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Last year, a magazine charged a $50 subscription fee. This year, the price will be increased by $10. If the magazine could lose 4 subscribers this year and still collect the same revenue as it did last year, how many subscribers did the magazine have last year?
(A) 20
(B) 21
(C) 22
(D) 23
(E) 24
(A) 20
(B) 21
(C) 22
(D) 23
(E) 24
Re: Last year, a magazine charged a $50 subscription fee. This
[#permalink]
27 May 2018, 13:13
27 May 2018, 13:13
Expert Reply
Explanation
Assign the variable s for the number of subscribers last year:
Last year:
$50 per subscription
\(s\) subscribers
This year:
$60 per subscription
\(s - 4\) subscribers
The question states that the magazine “could” lose 4 subscribers and that the magazine would then collect the same revenue as last year—don’t let the “could” throw you off. Calculate using this hypothetical situation:
\(50s = 60(s - 4)\)
\(50s = 60s - 240\)
\(-10s = -240\)
\(s = 24\)
Hence option E is correct!
Assign the variable s for the number of subscribers last year:
Last year:
$50 per subscription
\(s\) subscribers
This year:
$60 per subscription
\(s - 4\) subscribers
The question states that the magazine “could” lose 4 subscribers and that the magazine would then collect the same revenue as last year—don’t let the “could” throw you off. Calculate using this hypothetical situation:
\(50s = 60(s - 4)\)
\(50s = 60s - 240\)
\(-10s = -240\)
\(s = 24\)
Hence option E is correct!
Re: Last year, a magazine charged a $50 subscription fee. This
[#permalink]
23 Jun 2021, 09:57
23 Jun 2021, 09:57
50x= 60*(x-4)
x= 24
x= 24
