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Re: The measures of two angles of a parallelogram differ by 52 d [#permalink]
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Re: The measures of two angles of a parallelogram differ by 52 d [#permalink]
sandy wrote:
The measures of two angles of a parallelogram differ by 52 degrees. The number of degrees in the smaller angle is

(A) 38
(B) 52
(C) 64
(D) 76
(E) 128


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Opposites angle of a parallelogram is equal. And in the same side angles make 180 degrees total. So if you are getting two equations, one is for the addition of two angles = 180 and subtraction of two angles = 52. Now if you solve, you will get the smaller angle of 64 degrees.
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Re: The measures of two angles of a parallelogram differ by 52 d [#permalink]
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Since we are concerned with a smaller angle, it would be fine to solve for it only.

Let x= smaller angle & (x + 52) = larger angle [because the question states that two angles differ by 52]

2x + 2(x + 52) = 360
2x + 2x + 104 = 360
4x + 104 = 360
4x = 256
x = 64
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Re: The measures of two angles of a parallelogram differ by 52 d [#permalink]
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