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Re: DI Set #5 [#permalink]
soumya1989 wrote:

What was the approximate population of Town X in 1945?
A. 150
B. 750
C. 1500
D. 3000
E. 4500



When we check what was happening in 1945...
Image
we see that there were about 30 televisions.
We also see that there were about 25 people per television.
So, the total number of people =(30)(25)
= 750
Answer:
Show: ::
B


Cheers,
Brent
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From 1940 to 1955, the percent increase in the number of tel [#permalink]
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#GREpracticequestion From 1940 to 1955, the percent increase in the number of televisions was closest to .jpg
#GREpracticequestion From 1940 to 1955, the percent increase in the number of televisions was closest to .jpg [ 55.58 KiB | Viewed 6899 times ]


From 1940 to 1955, the percent increase in the number of televisions was closest to

A. 30

B. 130

C. 350

D. 450

E. 650
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Re: From 1940 to 1955, the percent increase in the number of tel [#permalink]
the trap here is the word "percent increase"
do not start finding the actual number
just the increase from 20
ie the difference between 90 and 20 which is 70
which is 350% of 20
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Re: DI Set #5 [#permalink]
GreenlightTestPrep wrote:
soumya1989 wrote:
Image

In 1955, the ratio of the number of televisions to the number of people was approximately
A. 1 to 13
B. 1 to 23
C. 1 to 26
D. 1 to 50
E. 1 to 90

From 1940 to 1955, the percent increase in the number of televisions was closest to
A. 30
B. 130
C. 350
D. 450
E. 600

What was the approximate population of Town X in 1945?
A. 150
B. 750
C. 1500
D. 3000
E. 4500

Show: :: Answer
A,C,B


In 1955, the ratio of the number of televisions to the number of people was approximately
A. 1 to 13
B. 1 to 23
C. 1 to 26
D. 1 to 50
E. 1 to 90

If we examine what's happening in 1955 with regard to population per television...
Image
...we see that there are approximately 13 people per 1 TV.

So, the ratio is 1 to 13

Answer:
Show: ::
A


Cheers,
Brent


Why are there 2 equal images?
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Re: DI Set #5-number of televisions to the number [#permalink]
Quote:
From 1940 to 1955, the percent increase in the number of televisions was closest to
A. 30
B. 130
C. 350
D. 450
E. 600


Can you, please, explain the second task? I had 300%. How can it be 350%?
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Re: DI Set #5-number of televisions to the number [#permalink]
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In 1940 is 20

In 1955 is 90

\(\frac{90-20}{20}=3.5\)

C is the answer
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