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The electricity used by the water heater was measured separately
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20 Sep 2022, 21:18
20 Sep 2022, 21:18
Expert Reply
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100% (01:37) wrong based on 5 sessions
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The electricity used by the water heater was measured separately and its cost per kilowatt-hour was one-half the cost per kilowatt-hour of the rest of the electricity used. The cost of the electricity used by the water heater was most nearly what fraction of the total cost of all the electricity used?
(A) 1/11
(B) 1/9
(C) 1/8
(D) 1/5
(E) It cannot be determined from the information given.
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GRE Math Essentials (2022)
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GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
Re: The electricity used by the water heater was measured separately
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27 Sep 2022, 13:19
27 Sep 2022, 13:19
Wouldnt it be 1/3?
If:
Energy used for the rest = $10
Energy used for Water = $10/2 = $5
Then
Total energy = $10+$5=15
Percentage of energy used on Water = $5/$15 = 1/3
If:
Energy used for the rest = $10
Energy used for Water = $10/2 = $5
Then
Total energy = $10+$5=15
Percentage of energy used on Water = $5/$15 = 1/3
Re: The electricity used by the water heater was measured separately
[#permalink]
10 Oct 2022, 13:09
10 Oct 2022, 13:09
1
Expert Reply
let per unit Cost be $1 for normal and %0.5 for water heating.
So Water heating Cost: 20% of 800 * 0.5 = $80.
Rest Cost: 80% of 800 * 1 = $640
Total Cost $80 + $640 = $720
So cost of the electricity used by the water heater/ total cost of all the electricity used = \(\frac{$80}{$720}\) = \(\frac{1}{9}\)
Answer: B
So Water heating Cost: 20% of 800 * 0.5 = $80.
Rest Cost: 80% of 800 * 1 = $640
Total Cost $80 + $640 = $720
So cost of the electricity used by the water heater/ total cost of all the electricity used = \(\frac{$80}{$720}\) = \(\frac{1}{9}\)
Answer: B
