Last visit was: 21 Nov 2024, 12:40 It is currently 21 Nov 2024, 12:40

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 30002
Own Kudos [?]: 36336 [8]
Given Kudos: 25927
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 30002
Own Kudos [?]: 36336 [0]
Given Kudos: 25927
Send PM
Intern
Intern
Joined: 27 Sep 2021
Posts: 5
Own Kudos [?]: 9 [3]
Given Kudos: 13
Send PM
Intern
Intern
Joined: 03 Feb 2016
Posts: 42
Own Kudos [?]: 28 [0]
Given Kudos: 6
Send PM
Re: GRE Quant - Percent % Theory [#permalink]
Carcass wrote:

Example: Lena’s grade was in the 80th percentile out of 120 grades in her class. In another class of 200 students there were 24 grades higher than Lena’s. If nobody had Lena’s grade, then Lena was what percentile of the two classes combined?

Solution:
Being in 80th percentile out of 120 grades means Lena outscored \(120*0.8=96\) classmates.

In another class she would outscored \(200-24=176\) students.

So, in combined classes she outscored \(96+176=272\). As there are total of \(120+200=320\) students, so Lena is in \(\frac{272}{320}=0.85=85%\), or in 85th percentile.[/textarea]


Since 24 students have a score higher than her, so wouldn't 175 students have a score lower than her considering her own grade in that class i.e., she would be the 176th student (200-24=176) and there will be 175 below her and 24 above her grade (175+1+24). (I'm assuming she's enrolled in both classes). Please clarify.
Verbal Expert
Joined: 18 Apr 2015
Posts: 30002
Own Kudos [?]: 36336 [0]
Given Kudos: 25927
Send PM
Re: GRE Quant - Percent % Theory [#permalink]
Expert Reply
ORIGINAL QUESTION IS:

Lena’s grade was in the 80th percentile out of 120 grades in her class. In another class of 200 students there were 24 grades higher than Lena’s. If nobody had Lena’s grade, then Lena was what percentile of the two classes combined?

If someone's grade is in \(x_{th}\) percentile of the \(n\) grades, this means that \(x%\) of people out of \(n\) has the grades less than this person.

So, being in 80th percentile out of 120 grades means Lena outscored \(120*0.8=96\) classmates.

In another class she would outscored \(200-24=176\) students.

So, in combined classes she outscored \(96+176=272\). As there are total of \(120+200=320\) students, so Lena is in \(\frac{272}{320}=0.85=85%\), or in 85th percentile.


Hope it helps.
Intern
Intern
Joined: 03 Feb 2016
Posts: 42
Own Kudos [?]: 28 [0]
Given Kudos: 6
Send PM
Re: GRE Quant - Percent % Theory [#permalink]
Carcass wrote:
ORIGINAL QUESTION IS:

Lena’s grade was in the 80th percentile out of 120 grades in her class. In another class of 200 students there were 24 grades higher than Lena’s. If nobody had Lena’s grade, then Lena was what percentile of the two classes combined?

If someone's grade is in \(x_{th}\) percentile of the \(n\) grades, this means that \(x%\) of people out of \(n\) has the grades less than this person.

So, being in 80th percentile out of 120 grades means Lena outscored \(120*0.8=96\) classmates.

In another class she would outscored \(200-24=176\) students.

So, in combined classes she outscored \(96+176=272\). As there are total of \(120+200=320\) students, so Lena is in \(\frac{272}{320}=0.85=85%\), or in 85th percentile.


Hope it helps.

Thank you for the answer. But my question remained unanswered that why wouldn't we consider Lena in this class. 24 students scored higher than her. If she were also part of the class than she would be one of the students and then 200-24(scored greater than Lena)-1(Lena)=175 scored less than Lena.
Verbal Expert
Joined: 18 Apr 2015
Posts: 30002
Own Kudos [?]: 36336 [0]
Given Kudos: 25927
Send PM
Re: GRE Quant - Percent % Theory [#permalink]
Expert Reply
There are two categories: one, the students who scored better than Lena, so their scores are definitely greater than her scores; two, those who didn't score better then Lena, so their scores are less than or equal to Lena's scores. Lena, herself is in the second category. The information that nobody has Lena's score is not relevant. What is important is how many outscored her:
on the first test - 0.2*120 = 24
on the second test - 24
In total, 24 + 24 = 48 out of 120 + 200 = 320 outscored Lena, and represent 48/320 = 15%. Therefore, Lena's score is in the 100 - 15 = 85th percentile.
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5030
Own Kudos [?]: 74 [0]
Given Kudos: 0
Send PM
Re: GRE Quant - Percent % Theory [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
Re: GRE Quant - Percent % Theory [#permalink]
Moderators:
GRE Instructor
83 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne