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In Triangle ABC shown in the figure, BC = 3 and AC = 4. What
[#permalink]
19 Feb 2018, 23:14
19 Feb 2018, 23:14
In Triangle ABC shown in the figure, BC = 3 and AC = 4. What is the length of the line segment CD?
A. \(3\)
B. \(\frac{15}{4}\)
C. \(5\)
D. \(\frac{16}{3}\)
E. \(\frac{20}{3}\)
A. \(3\)
B. \(\frac{15}{4}\)
C. \(5\)
D. \(\frac{16}{3}\)
E. \(\frac{20}{3}\)
Attachments
IMG_20180220_123859.jpg [ 310.48 KiB | Viewed 1657 times ]
Re: In Triangle ABC shown in the figure, BC = 3 and AC = 4. What
[#permalink]
20 Feb 2018, 03:24
20 Feb 2018, 03:24
Expert Reply
Please follow the rules for posting.
The questions must go the right sub-forum.
Thank you
The questions must go the right sub-forum.
Thank you
Re: In Triangle ABC shown in the figure, BC = 3 and AC = 4. What
[#permalink]
20 Feb 2018, 16:53
20 Feb 2018, 16:53
1
Expert Reply
Could you please share the source of the question?
This question cannot be solved without trigonometry or similar triangles. Both of which are not part of GRE.
The answer should be \(\frac{16}{3}\)
This question cannot be solved without trigonometry or similar triangles. Both of which are not part of GRE.
The answer should be \(\frac{16}{3}\)
