Re: what is the largest prime number that
[#permalink]
12 Jul 2026, 07:03
Step 1: Find the ranges for x and y .
- Given \(x^2<81\) , taking the square root gives the range for x :
\(-9<x<9\)
- Given \(y^2<25\) , taking the square root gives the range for y :
\(-5<y<5\)
Step 2: Find the maximum possible upper bound for the expression x-2 y . To make x-2 y as large as possible, you need to maximize x and minimize y :
- The upper bound for x is \(9(x<9)\) .
- The lower bound for y is \(-5(y>-5) \). Multiplying this inequality by -2 reverses the inequality sign:
\(-2 y<10\)
Now, add the two upper bounds together:
\((x)+(-2 y)<9+10
\)
\(x-2 y<19\)
Step 3: Determine the largest prime number within this range.
The value of x-2 y must be strictly less than 19 . Since the question does not state that x and y must be integers, x-2 y can equal any real number up to (but not including) 19.
The largest prime number strictly less than 19 is 17.
(Example check: If x=8 and y=-4.5 , both satisfy the initial conditions, and 8- 2(-4.5)=17 .)
Correct Answer: D) 17