That's it ??

1 and -1 ??

Did you really evaluate upfront the question ??

The answer will be changed if we take x = 4 and y = -8
Ok It looked so easy that i didnt test other values

Let's test some possible values of x and y

case i: Since \(x>0>y\), one possible pair of values is \(x=1\) and \(y=-1\)
We get:
Quantity A: \(x-y = 1 - (-1) = 2 \)
Quantity B: \((x+y)^2=(1+(-1))^2 = 0^2 = 0\)
In this case, Quantity A is greater

case ii: Since \(x>0>y\), another possible pair of values is \(x=5\) and \(y=-1\)
We get:
Quantity A: \(x-y = 5 - (-1) = 6 \)
Quantity B: \((x+y)^2=(5+(-1))^2 = 4^2 = 16\)
In this case, Quantity B is greater

Answer: D

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Testing with x = -1 and y = 1 --> we get A = 2 and Qty B = 0 --> Ans A
with y = -2, and x = 5 we get Qty A = 7 and Qty B = 9. which is B

Thus ans is D.

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