Last visit was: 22 Nov 2024, 00:29 It is currently 22 Nov 2024, 00:29
Decision Tracker
My Rewards
New comers' posts
New posts
Unanswered

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more
Close

Request Expert Reply

Confirm Cancel
PREVIOUS TOPIC
NEXT TOPIC

(x+2)(x-2)

Tags :
Find Similar Topics  About  Add a Tag

Show Tags
Hide Tags

User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30003
Own Kudos [?]: 36341 [0]
Given Kudos: 25927
Send PM
(x+2)(x-2) [#permalink] New post   03 Oct 2018, 23:21
2
Expert Reply
00:00

Question Stats:

53% (01:27) correct 46% (01:25) wrong based on 146 sessions

Hide Show timer Statistics

Quantity A
Quantity B
\((x+2)(x-2)\)
\(\frac{-5(x^2-25)(x-1)}{(x+5)(x^2-6x+5)}\)


Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
ShowHide Answer
Official Answer
A
avatar
novice07
Intern
Intern
Joined: 20 Mar 2018
Posts: 39
Own Kudos [?]: 127 [0]
Given Kudos: 0
GRE 1: Q163 V149

GRE 2: Q168 V162
GPA: 3.5
Send PM
Reviews Badge
Re: (x+2)(x-2) [#permalink] New post   04 Oct 2018, 01:00
1
On simplifying quantity B, it reduces to only -5.

Quantity A: x^2 - 4
As x^2 will always be greater than or equal to 0, the minimum value of quantity A is -4.

Hence A
avatar
Hovsep
Manager
Manager
Joined: 23 Oct 2018
Posts: 57
Own Kudos [?]: 0 [0]
Given Kudos: 0
Send PM
Re: (x+2)(x-2) [#permalink] New post   24 Oct 2018, 06:15
it was too complicated.
avatar
chetan2u
Supreme Moderator
Joined: 01 Nov 2017
Posts: 371
Own Kudos [?]: 470 [0]
Given Kudos: 0
Send PM
Re: (x+2)(x-2) [#permalink] New post   24 Oct 2018, 08:33
1
Expert Reply
Carcass wrote:
Quantity A
Quantity B
\((x+2)(x-2)\)
\(\frac{-5(x^2-25)(x-1)}{(x+5)(x^2-6x+5)}\)


Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.



A=(\((x+2)(x-2)=x^2-4\)).. min value will be -4 as \(x^2\geq{0}\)
B=\(\frac{-5(x^2-25)(x-1)}{(x+5)(x^2-6x+5)}=\frac{-5(x-5)(x+5)(x-1)}{(x+5)(x^2-5x-x-5)}=\frac{-5(x+5)(x-1)(x-5)}{(x+5)(x-1)(x-5)}=-5\)

So A>B

A
avatar
Fatemeh
Manager
Manager
Joined: 22 Feb 2018
Posts: 163
Own Kudos [?]: 214 [0]
Given Kudos: 0
Send PM
Re: (x+2)(x-2) [#permalink] New post   28 Nov 2018, 12:47
Answer: A
We just try to simplify them:

A= (x+2)(x-2) = x^2-4

B= -5 * (x^2 - 25)(x-1) / (x+5)(x^2-6x+5) =
-5 * (x-5)(x+5)(x-1) / (x+5)(x-5)(x-1) =
-5

A= x^2 -4 and B=-5, as x^2 is something positive, it can at least be zero, so x^2-4 is definitely more than -4, So A is bigger than B.
avatar
B
Divu1112
Intern
Intern
Joined: 07 Apr 2021
Posts: 20
Own Kudos [?]: 15 [0]
Given Kudos: 57
Send PM
Re: (x+2)(x-2) [#permalink] New post   01 Jun 2021, 08:05
quantity A: x^2-4
if x=0 then also value is -4

quantity 2: after solving the equation we will get -5

hence option A is the correct answer.
avatar
B
nikitap
Intern
Intern
Joined: 20 Dec 2022
Posts: 15
Own Kudos [?]: 15 [1]
Given Kudos: 249
Send PM
Re: (x+2)(x-2) [#permalink] New post   06 Mar 2023, 10:29
1
QA -> x^2 -4
QB -> -5

Add +4 in QA and QB
QA -> x^2
QB -> -1

we know that square of any number is always greater than or equal to 0.

Therefore, QA > QB
Prep Club for GRE Bot
gmatclubot
Re: (x+2)(x-2) [#permalink]
06 Mar 2023, 10:29
Moderators:
adewale223
GRE Instructor
84 posts
bronaugust
GRE Forum Moderator
37 posts
BrushMyQuant
Moderator
1111 posts
VibhuAnurag
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Main navigation

Partners

GRE Resources

www.ets.org/gre | About | Terms and Conditions and Privacy Policy | Prep Club for GRE Rules | Contact