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Carcass
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x < 0 [#permalink] New post   31 Aug 2016, 07:18
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\(x < 0\)

Quantity A
Quantity B
\(x^5\)
\(x^4\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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Saurabh03121992
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Re: x < 0 [#permalink] New post   31 Aug 2016, 07:45
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B

A negative raised to the power of an even no is always greater than an odd. Although 0 is the only exception in even nos as anything raised to it is 1.

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Re: x < 0 [#permalink] New post   31 Aug 2016, 10:42
2
Carcass wrote:
\(x < 0\)

Quantity A
Quantity B
\(X^5\)
\(X^4\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Another approach.

We're told that x < 0, which means x ≠ 0.
If x ≠ 0, then x⁴ is POSITIVE

So, let's divide both quantities by x⁴ to get:
Quantity A: x
Quantity B: 1

Since we're told that x < 0, we can be certain that quantity B is greater.

Answer:
Show: ::
B


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QOTD # 1 X^5 and X^4 [#permalink] New post   07 Sep 2016, 02:24
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\(x < 0\)

Quantity A
Quantity B
\(x^5\)
\(x^4\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Carcass
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Re: QOTD # 1 X^5 and X^4 [#permalink] New post   07 Sep 2016, 02:26
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Explanation

If x < 0, then \(x^5\) < 0 and \(x^4\) > 0. Thus \(x^5\) < \(x^4\) , and the correct answer is Choice B.
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GreenlightTestPrep
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Re: QOTD # 1 X^5 and X^4 [#permalink] New post   07 Sep 2016, 06:17
1
Carcass wrote:

x < 0
Quantity A
Quantity B
\(X^5\)
\(X^4\)




Another approach:
Quantity A: x⁵
Quantity B: x⁴

Since we're told that x < 0, we can be certain that x ≠ 0.
From this, we can conclude that x⁴ is POSITIVE, which means we can divide both quantities by x⁴ to get:
Quantity A: x
Quantity B: 1

Since we're told that x < 0 (i.e., x is NEGATIVE), we can be certain that 1 is greater than x

Answer:
Show: ::
B


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Re: QOTD # 1 X^5 and X^4 [#permalink]
07 Sep 2016, 06:17
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