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x < 5 ; y < z

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x < 5 ; y < z [#permalink] New post   29 Jun 2022, 08:58
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x < 5 ; y < z

Quantity A
Quantity B
x+y
z+5


A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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B
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x < 5 ; y < z [#permalink] New post   05 Jul 2022, 06:40
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Quote:
The expression in column B can be written as 5 + z, because of the commutative property of addition. Since it is given that x < 5 and also that y < z, then the quantity in column A, x + y is less than the quantity in column B, z + 5, because of the one to one correspondence of the terms and the fact that you are adding.
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Re: x < 5 ; y < z [#permalink] New post   17 Jun 2024, 04:06
how do we know it is B? we don't have any details of x y or z, appreciate any help, thanks
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Re: x < 5 ; y < z [#permalink] New post   17 Jun 2024, 04:42
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No

QB iz z+5 or 5+z is the same.

Now, 5+z means that z could be fraction such as 1/2 or an integer such us at least 1 or 1 billion.
Suppose 1 and suppose we take into account integers to picking up

5+1=6

x<5 so at least x=4 or less

y<z so it must be 0 or less (also negatives numbers)

QA is x+y=4+0=4

QB is 6

B is the answer
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Re: x < 5 ; y < z [#permalink]
17 Jun 2024, 04:42
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