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In the circle inside the square is greater x+y/2 or 5
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21 Jan 2025, 00:34
21 Jan 2025, 00:34
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Question Stats:
50% (01:19) correct
50% (01:12) wrong based on 6 sessions
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GRE x+y2 or 5.png [ 18.37 KiB | Viewed 668 times ]
Quantity A |
Quantity B |
\(\frac{x+y}{2}\) |
\(5\) |
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Re: In the circle inside the square is greater x+y/2 or 5
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02 Mar 2025, 13:30
02 Mar 2025, 13:30
Expert Reply
The length of the square is same as the diameter of the circle which is inscribed in it.
It is clear from the figure that the sum of $\(x\)$ and $\(y\)$ is less than the diameter of the circle, so is less than the length of the side of the square. So, we get $\(x+y<10\)$ i.e. $\(\frac{x+y}{2}<\frac{10}{2}=5\)$
Hence column $\(B\)$ has higher quantity when compared with column $\(A\)$, so the answer is (B).
It is clear from the figure that the sum of $\(x\)$ and $\(y\)$ is less than the diameter of the circle, so is less than the length of the side of the square. So, we get $\(x+y<10\)$ i.e. $\(\frac{x+y}{2}<\frac{10}{2}=5\)$
Hence column $\(B\)$ has higher quantity when compared with column $\(A\)$, so the answer is (B).
Re: In the circle inside the square is greater x+y/2 or 5
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10 Apr 2025, 01:07
10 Apr 2025, 01:07
1
how can we be sure that X and Y cannot be meet at the diagonal position?
in this case, the answer could also be 5, leading to D...
in this case, the answer could also be 5, leading to D...
