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x < y < z, where x, y and z are the lengths of the edges of a cuboid
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05 Jan 2025, 22:41
05 Jan 2025, 22:41
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75% (01:12) correct
25% (01:09) wrong based on 12 sessions
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x < y < z, where x, y and z are the lengths of the edges of a cuboid
Quantity A |
Quantity B |
Volume of the cuboid with edges having lengths x+10,y, and z |
Volume of the cuboid with edges having lengths x,y, and z+10 |
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Re: x < y < z, where x, y and z are the lengths of the edges of a cuboid
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17 Feb 2025, 02:34
17 Feb 2025, 02:34
Expert Reply
OFFICIAL EXPLANATION
We know $\(\mathrm{x}<\mathrm{y}<\mathrm{z}\)$ are the length of the edges of a Cuboid.
Volume of a Cuboid $\(=\)$ Length $\(\times\)$ Breadth $\(\times\)$ Height
So, the volume of Cuboid having edges $\((x+10), y \& z\)$ is $\((x+10) \times y \times z=x y z+10 y z\)$ \& the volume of the Cuboid having edges $\(x, y \&(z+10)\)$ is $\(x \times y \times(z+10)=x y z+10 x y\)$
The comparison between $\(x y z+10 y z \& x y z+10 x y\)$ is same as comparing $\(10 y z \& 10 x y\)$ i.e. comparing z with x .
As $\(Z>x\)$, column $\(A\)$ has higher quantity when compared with column $\(B\)$.
Hence the answer is (A).
We know $\(\mathrm{x}<\mathrm{y}<\mathrm{z}\)$ are the length of the edges of a Cuboid.
Volume of a Cuboid $\(=\)$ Length $\(\times\)$ Breadth $\(\times\)$ Height
So, the volume of Cuboid having edges $\((x+10), y \& z\)$ is $\((x+10) \times y \times z=x y z+10 y z\)$ \& the volume of the Cuboid having edges $\(x, y \&(z+10)\)$ is $\(x \times y \times(z+10)=x y z+10 x y\)$
The comparison between $\(x y z+10 y z \& x y z+10 x y\)$ is same as comparing $\(10 y z \& 10 x y\)$ i.e. comparing z with x .
As $\(Z>x\)$, column $\(A\)$ has higher quantity when compared with column $\(B\)$.
Hence the answer is (A).
gmatclubot
Re: x < y < z, where x, y and z are the lengths of the edges of a cuboid [#permalink]
17 Feb 2025, 02:34
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