GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
y = 2x+20, where y is an integer and 0 < x < 19.
[#permalink]
26 Feb 2025, 02:07
26 Feb 2025, 02:07
Expert Reply
00:00
Question Stats:
0% (00:00) correct
100% (01:02) wrong based on 1 sessions
Hide Show timer Statistics
\( y = 2x+20\), where y is an integer and \(0 < x < 19\).
Quantity A |
Quantity B |
The number of different possible values of y |
18 |
- Part of the project: GRE Quant & Verbal ADVANCED Daily Challenge 2025 NEW Edition - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
- Also replying to the unanswered questions
Manager
Joined: 11 Nov 2023
Posts: 220
Given Kudos: 77
WE:Business Development (Advertising and PR)
Re: y = 2x+20, where y is an integer and 0 < x < 19.
[#permalink]
26 Feb 2025, 09:58
26 Feb 2025, 09:58
1
It's a bit tricky because if you assume that x must be an integer, then there are 18 possible values of y.
However, since y = 2x + 20, for every "half" integer value of x (e.g., when x = 0.5, 1.5), we get an integer value for y.
E.g., if x = 0.5, y = 2(0.5)+20 = 21
Since 21 is an integer, it satisfies the given constraints.
Therefore, the minimum possible value of x is 0.5 and the max is 18.5, and there are 18*2 = 36 total possible values of y.
However, since y = 2x + 20, for every "half" integer value of x (e.g., when x = 0.5, 1.5), we get an integer value for y.
E.g., if x = 0.5, y = 2(0.5)+20 = 21
Since 21 is an integer, it satisfies the given constraints.
Therefore, the minimum possible value of x is 0.5 and the max is 18.5, and there are 18*2 = 36 total possible values of y.
gmatclubot
Re: y = 2x+20, where y is an integer and 0 < x < 19. [#permalink]
26 Feb 2025, 09:58
Moderators:
